Answer :
[tex]initial \: \: \: \: velocity \:(u) = 17m {s}^{ - 1} \\ acceleration \: (a) = 2.5 m {s}^{ - 2} \\ time \: \: \: \: taken \: (t) = 4s \\ let \: \: \: \: the \: \: \: \: distance \: \: \: \: travelled \: \: \: \: by \: \: \: \: \\ the \: \: \: \: car \: \: \: \: be \: \: \: \: s \: m. \\ by \: \: \: \: using \: \: \: \: the \: \: \: \: equation \\ s = ut + \frac{1}{2} a {t}^{2} \: \: \: we \: \: \: \: get \\ s = 17 \times 4 + \frac{1}{2}(2.5) {(4)}^{2} \\ \: \: \: \: = 68 + \frac{1}{2} \times 2.5 \times 16 \\ \: \: \: \: = 68 + 10 = 78 \\ [/tex]